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A060334
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The sequence A006863 (shifted by one) seems to be counting the periodic points for a map. If so, then this is the sequence of the numbers of orbits of length n.
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0
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24, 108, 160, 60, 48, 10800, 0, 1980, 3136, 1272, 48, 5440, 0, 480, 11408, 1020, 0, 7671552, 0, 53448, 7200, 216, 48, 179520, 0, 480, 2128, 240, 48, 227138600, 0
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OFFSET
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1,1
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LINKS
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FORMULA
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If b(n) is the (n+1)st term of A006863, then a(n)=(1/n)* Sum_{d|n}\mu(d)b(n/d)
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EXAMPLE
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a(3) = 160 because the 4th term of A006863 is 504 and the 2nd term is 24, so there should be (504-24)/3 = 160 orbits of length 3.
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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