

A056895


If the smallest prime with a square excess of n is p then a(n)^2 = p  n.


3



1, 1, 2, 3, 6, 5, 4, 9, 8, 7, 6, 7, 10, 15, 8, 9, 24, 11, 12, 21, 16, 13, 12, 13, 16, 15, 14, 17, 18, 31, 20, 27, 20, 23, 18, 19, 22, 21, 20, 23, 24, 23, 24, 27, 28, 29, 30, 25, 38, 39, 26, 31, 30, 35, 28, 45, 34, 31, 42, 31, 34, 33, 32, 33, 36, 35, 34, 75, 40, 37, 36, 41, 48, 45
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OFFSET

1,3


LINKS



FORMULA



EXAMPLE

a(4)=3 because the smallest prime with a square excess of 4 is 13 and 13  4 = 3^2.


MATHEMATICA

a = {}; Do[p = 2; While[n != p  (r = Floor@Sqrt[p])^2, p = NextPrime[p]]; AppendTo[a, r], {n, 74}]; a (* Ivan Neretin, May 02 2019 *)


PROG

(PARI) a(n) = {my(p=2); while(n != psqrtint(p)^2, p = nextprime(p+1)); sqrtint(p  n); } \\ Michel Marcus, May 05 2019


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



