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A056055
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Integers k > 1 such that the decimal expansion of 1/k contains k as a string. (If the decimal expansion terminates, trailing zeros do not count.)
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1
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3, 6, 7, 14, 17, 28, 58, 59, 83, 86, 87, 89, 97, 118, 167, 197, 228, 281, 313, 316, 339, 367, 379, 383, 456, 458, 469, 529, 541, 543, 569, 577, 587, 593, 607, 618, 626, 629, 647, 669, 673, 677, 678, 683, 687, 701, 709, 719, 722, 727, 729, 767, 771, 772, 778
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OFFSET
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1,1
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COMMENTS
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The sequence is probably infinite, since long-period primes (cf. A006883) especially with high first digit are likely candidates, but is there a proof? Does any k with finite expansion of 1/k (i.e., k = 2^j * 5^m) occur?
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LINKS
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EXAMPLE
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118 is a term since 1/118 = 0.00847457627118... contains "118".
100 is not a term because 1/100 = 0.01 does not contain "100" (0.0100 does not count).
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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Ulrich Schimke (ulrschimke(AT)aol.com)
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STATUS
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approved
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