login
A055441
Distribution of first digit of mantissa following Benford's law, using largest remainder method with Hare quotas.
4
1, 2, 3, 4, 1, 5, 6, 7, 1, 2, 8, 1, 3, 9, 2, 1, 4, 5, 1, 2, 3, 1, 6, 7, 1, 2, 4, 3, 1, 8, 2, 1, 5, 9, 1, 3, 4, 2, 1, 6, 7, 1, 2, 3, 5, 1, 4, 8, 1, 2, 6, 1, 3, 2, 1, 9, 4, 5, 1, 2, 3, 1, 7, 6, 1, 2, 4, 3, 1, 8, 5, 2, 1, 9, 1, 3, 2, 4, 1, 7, 6, 1, 2, 5, 3, 1, 8, 4, 1, 2, 1, 3, 7, 2, 1, 5, 6, 1, 4, 2, 9, 3, 1, 8, 1
OFFSET
1,2
COMMENTS
From Pontus von Brömssen, Mar 31 2026: (Start)
The apportionment method used here is an iterative version of the largest remainder method with Hare quotas, successively allocating 1 item (or seat) at a time to the element k maximizing n*p(k)-c(k), where p(k) is the probability mass of k and c(k) is the number of occurrences of k among the previous terms. This method is also used in A241773, for example. In some cases, the result differs from the non-iterative version (the Hamilton method). The latter method first allocates c(k) = floor(n*p(k)) items to element k; thereafter, the remaining items (if any) are allocated to elements k in decreasing order of the remainders n*p(k)-c(k). With this method, it may happen that the number of items allocated to a certain element decreases when n increases (the Alabama paradox); obviously, that does not happen for the iterative method, because no items are ever removed.
For the distribution considered here (Benford's law), the allocations of the iterative and non-iterative versions differ for n = 9, 26, 49, 52, 65, 82, 83, 89, 95, ... . It appears that all these cases are due to the Alabama paradox occurring in the Hamilton method, i.e., the number of items allocated to some element k, when n items are available, is smaller than it is for some smaller number of items. For the first 9 terms, for example, the numbers of occurrences of 1-9 in this sequence are (3, 1, 1, 1, 1, 1, 1, 0, 0), but the Hamilton method would give (3, 2, 1, 1, 1, 1, 0, 0, 0).
(End)
LINKS
Pontus von Brömssen, Table of n, a(n) for n = 1..10000
Eric Weisstein's World of Mathematics, Benford's Law.
Wikipedia, Hare quota.
Wikipedia, Quota method.
EXAMPLE
a(50) = 2 so that after 50 terms we have had 15 1's, 9 2's, 6 3's, 5 4's, 4 5's, 3 6's, 3 7's, 3 8's and 2 9's.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Henry Bottomley, May 17 2000
STATUS
approved