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A055114
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Numbers k such that the continued fraction for m/k contains a term >= 3 for every 1 <= m < k.
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3
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23, 37, 53, 59, 61, 83, 103, 107, 113, 127, 137, 139, 149, 151, 197, 211, 223, 227, 229, 331, 347, 349, 353, 359, 383, 421, 439, 461, 479, 491, 509, 523, 529, 541, 557, 563, 569, 607, 631, 739, 751, 757, 761, 769, 797, 809, 811, 821, 823, 827, 829, 839, 851
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OFFSET
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1,1
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COMMENTS
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LINKS
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EXAMPLE
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23 is in sequence because continued fractions for 1/23, 2/23, ..., 22/23 each contain a term >= 3.
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MATHEMATICA
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q[n_] := AllTrue[Range[1, n - 1], Max[ContinuedFraction[#/n]] > 2 &]; Select[Range[2, 1000], q] (* Amiram Eldar, Jun 25 2022 *)
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PROG
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(PARI) drop(v)=v[2..#v]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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