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 A053300 Continued fraction for Pi/2. 7
 1, 1, 1, 3, 31, 1, 145, 1, 4, 2, 8, 1, 6, 1, 2, 3, 1, 4, 1, 5, 1, 41, 1, 2, 3, 7, 1, 1, 1, 27, 1, 1, 1, 2, 1, 2, 1, 1, 2, 1, 1, 49, 2, 1, 4, 3, 6, 2, 1, 3, 3, 17, 1, 3, 2, 1, 6, 3, 1, 6, 26, 3, 1, 1, 3, 4, 3, 2, 14, 11, 1, 4, 1, 1, 5, 2, 8, 8, 2, 80, 1, 1, 22, 2, 11, 2, 1 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,4 LINKS Harry J. Smith, Table of n, a(n) for n = 0..20000 Michael A. Filaseta, Allen Stenger, D. Callan and Z. Franco, Solution to Problem 10640: When a Multiple of Pi/2 is Close to an Integer, Amer. Math. Monthly, 107 (2000), 177-178. I. Rosenholtz, Tangent sequences, world records, ..., Math. Mag., 72 (No. 5, 1999), 367-376. G. Xiao, Contfrac EXAMPLE 1.57079632679489661923132169... = 1 + 1/(1 + 1/(1 + 1/(3 + 1/(31 + ...)))). - Harry J. Smith, May 31 2009 MATHEMATICA ContinuedFraction[ Pi/2, 100 ] PROG (PARI) { allocatemem(932245000); default(realprecision, 21000); x=contfrac(Pi/2); for (n=0, 20000, write("b053300.txt", n, " ", x[n+1])); } \\ Harry J. Smith, May 31 2009 (Magma) R:= RealField(); ContinuedFraction(Pi(R)/2); // G. C. Greubel, May 24 2018 CROSSREFS Cf. A001203. Cf. A019669 (decimal expansion). - Harry J. Smith, May 31 2009 Sequence in context: A145385 A059232 A068698 * A322777 A089281 A212729 Adjacent sequences: A053297 A053298 A053299 * A053301 A053302 A053303 KEYWORD nonn,cofr AUTHOR N. J. A. Sloane, Mar 21 2000 STATUS approved

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Last modified December 9 04:13 EST 2022. Contains 358698 sequences. (Running on oeis4.)