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A049281
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Numerators of coefficients in power series for -log(1+x)*log(1-x).
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6
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1, 5, 47, 319, 1879, 20417, 263111, 52279, 1768477, 33464927, 166770367, 3825136961, 19081066231, 57128792093, 236266661971, 7313175618421, 14606816124167, 102126365345729, 3774664307989373, 3771059091081773
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OFFSET
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1,2
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LINKS
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FORMULA
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a(n)/A069685(n) = Integral_{x=0..1} x^(n-1)*log(1 + 1/sqrt(x)) dx = 1/n*Sum_{k=0..2*n-2} (-1)^k/(2*n-1-k).
a(n) = numerator((1/n)*Sum_{k=1..2*n-1} (-1)^(k-1)/k ). Cf. A058313.
a(n) = numerator((1/2)*binomial(2*n,n)*Sum_{k=0..n-1} (-1)^k* binomial(n-1,k)/(n + k)^2 ).
The coefficients in the expansion of log(1 + x)*log(1 - x) are given by (1/2)*binomial(2*n,n)*Integral_{x = 0..1} (x*(1 - x))^(n-1)*log(x) dx.
log(1 + x)*log(1 - x) = (1/2)*Integral_{z = 0..1} log(z)/(z*(1 - z)) * (1/sqrt( 1 - 4*x^2*z*(1 - z) ) - 1) dz. (End)
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EXAMPLE
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-log(1 + x)*log(1 - x) = x^2 + 5/12*x^4 + 47/180*x^6 + 319/1680*x^8 + ...
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MAPLE
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seq(numer(1/n*add( (-1)^k/(2*n-1-k), k = 0..2*n-2)), n = 1..20); # Peter Bala, Feb 21 2017
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PROG
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(GAP) List(List([1..25], n->(1/n)*Sum([1..2*n-1], k->(-1)^(k-1)/k)), NumeratorRat); # Muniru A Asiru, Jun 01 2018
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CROSSREFS
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KEYWORD
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easy,frac,nonn
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AUTHOR
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STATUS
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approved
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