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 A048852 Difference between b^2 (in c^2=a^2+b^2) and product of successive prime pairs. 1
 0, 3, 10, 14, 44, 26, 68, 38, 92, 174, 62, 222, 164, 86, 188, 318, 354, 122, 402, 284, 146, 474, 332, 534, 776, 404, 206, 428, 218, 452, 1778, 524, 822, 278, 1490, 302, 942, 978, 668, 1038, 1074, 362, 1910, 386, 788, 398, 2532, 2676, 908, 458, 932, 1434, 482 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 LINKS FORMULA Find b^2 in Pythagorean formula c^2=a^2+b^2. Subtract product of successive prime pair at same a(n) beginning at 2*2. For n>0, a(n) = A000040(n+1)^2 - A000040(n) * A000040(n+1). - Mamuka Jibladze, Mar 24 2017 EXAMPLE a(3)=10. Product of 3rd prime pair 3*5=15 (after 2*2=4 and 2*3=6). b^2=25 (in c^2=a^2+b^2) where c^2=34 and a^2=9. Then 25-15=10. CROSSREFS Cf. A048851, A006094. A291463. Sequence in context: A024593 A128930 A328091 * A226101 A141463 A134102 Adjacent sequences:  A048849 A048850 A048851 * A048853 A048854 A048855 KEYWORD easy,nonn AUTHOR STATUS approved

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Last modified July 30 15:06 EDT 2021. Contains 346359 sequences. (Running on oeis4.)