|
|
A038203
|
|
Number of distinct values of factorials mod n.
|
|
4
|
|
|
1, 2, 3, 3, 4, 3, 5, 4, 5, 5, 6, 4, 10, 6, 5, 5, 12, 5, 12, 5, 6, 7, 17, 4, 8, 11, 8, 7, 19, 5, 21, 6, 8, 13, 7, 6, 26, 13, 11, 5, 29, 6, 26, 8, 6, 18, 31, 5, 11, 8, 13, 12, 35, 8, 9, 7, 14, 20, 37, 5, 41, 22, 7, 8, 13, 8, 42, 14, 18, 7, 39, 6, 44, 27, 8, 15, 11, 11, 49, 6, 9, 30, 55, 7
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
Assuming k! mod n is uniformly distributed mod n up to k = A002034(n), the first k! == 0 (mod n). This gives a(n) ~= (1-(1-1/n)^k)*n, which empirically appears to be a good estimate. For prime p, A002034(p) = p, so we would expect a(p) ~= (1-(1-1/p)^p)*p ~= (1-1/e)*p = 0.63212 p for large primes p. - David W. Wilson, Aug 01 2016
|
|
LINKS
|
|
|
EXAMPLE
|
a(15)=5 since factorials are 1, 2, 6, 24, 120, etc. which mod 15 are 1, 2, 6, 9, 0, etc. and so there are 5 distinct values.
|
|
MATHEMATICA
|
nn=90; With[{frls=Range[nn]!}, Table[Length[Union[Mod[#, n]&/@frls]], {n, nn}]] (* Harvey P. Dale, Oct 05 2011 *)
|
|
PROG
|
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|