OFFSET
1,1
FORMULA
a(n) = ceiling(sqrt(6*10^n)), n > 0.
PROG
(Python)
from math import isqrt
def a(n): return isqrt(6*10**n) + 1
print([a(n) for n in range(1, 28)]) # Michael S. Branicky, Aug 25 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Patrick De Geest, Nov 15 1998
STATUS
approved