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A032426
Sum_{n>=0} a(n)/10^n = exp(1).
1
2, 6, 10, 16, 19, 34, 37, 44, 38, 43, 47, 70, 52, 63, 68, 56, 82, 92, 106, 83, 96, 90, 92, 95, 124, 122, 116, 97, 130, 123, 109, 124, 113, 119, 116, 172, 161, 154, 119, 148, 172, 185, 181, 143, 161, 164, 179, 162
OFFSET
0,1
COMMENTS
From definition of exp(1) = Sum_{n>=0} 1/n!.
Each term of the sum is aligned this way.
1.
1.
0.5000000000000000000000000000000...
0.1666666666666666666666666666667...
0.0416666666666666666666666666667...
0.0083333333333333333333333333333...
0.0013888888888888888888888888889...
0.0001984126984126984126984126984...
0.0000248015873015873015873015873...
0.0000027557319223985890652557319...
0.0000002755731922398589065255732...
0.0000000250521083854417187750521...
0.0000000020876756987868098979210...
And the sum is taken for each column.
LINKS
Sean A. Irvine, Java program (github)
CROSSREFS
Sequence in context: A370114 A137236 A124198 * A220453 A195957 A354425
KEYWORD
nonn,base
AUTHOR
STATUS
approved