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A023745
Plaindromes: numbers whose digits in base 3 are in nondecreasing order.
10
0, 1, 2, 4, 5, 8, 13, 14, 17, 26, 40, 41, 44, 53, 80, 121, 122, 125, 134, 161, 242, 364, 365, 368, 377, 404, 485, 728, 1093, 1094, 1097, 1106, 1133, 1214, 1457, 2186, 3280, 3281, 3284, 3293, 3320, 3401, 3644, 4373, 6560, 9841, 9842, 9845, 9854
OFFSET
1,3
FORMULA
Numbers that in ternary are the concatenation of i 1's with j 2's, i, j>=0. Also a(n) = A073216(n+1) - 1. Proof: Write a(n) as 1{m}2{n}, then adding 1 gives 1{m-1}20{n} for m>0 and 10{n} for m=0. Doubling yields 10{m-1}10{n} or 20{n}, respectively. These two forms exactly describe the forms of sums of two powers of 3, the two powers being 3^n and 3^(m+n). - Hugo van der Sanden
EXAMPLE
In base 3 these numbers are 0, 1, 2, 11, 12, 22, 111, 112, 122, 222, 1111, 1112, ... [corrected by Sean A. Irvine, Jun 10 2019]
MATHEMATICA
Select[Range[0, 10000], !Negative[Min[Differences[IntegerDigits[ #, 3]]]]&] (* or *) With[{nn=10}, FromDigits[#, 3]&/@Union[Flatten[Table[ PadRight[ PadLeft[{}, n, 1], x, 2], {n, 0, nn}, {x, 0, nn}], 1]]] (* Harvey P. Dale, Oct 12 2011 *)
Select[Range[0, 10000], LessEqual@@IntegerDigits[#, 3]&] (* Ray Chandler, Jan 06 2014 *)
PROG
(Python)
from math import isqrt
def A023745(n): return (3**(a:=(k:=isqrt(m:=n<<1))+(m>k*(k+1))-1)+3**(n-1-(a*(a+1)>>1))>>1)-1 # Chai Wah Wu, Apr 08 2025
CROSSREFS
Cf. A023746 onwards. In base 2 we get A000225.
Sequence in context: A334522 A102829 A031988 * A217136 A294944 A178656
KEYWORD
nonn,base,easy
EXTENSIONS
Change offset to 1 by Ray Chandler, Jan 06 2014
STATUS
approved