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A023395 Only Fermat number divisible by A023394(n) is 2^2^a(n) + 1. 1
0, 1, 2, 3, 5, 4, 12, 6, 11, 11, 9, 5, 18, 12, 10, 12, 23, 16, 15, 10, 19, 12, 19, 13, 36, 21, 38, 32, 25, 17, 39, 6, 26, 27, 30, 30, 8, 12, 15, 29, 38, 7, 25, 27, 36, 42, 25, 13, 13, 55 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
From Jianing Song, Mar 02 2021: (Start)
2^(a(n)+1) is the multiplicative order of 2 modulo A023394(n).
Each k occurs A046052(k) times in this sequence provided that F(k) = 2^2^k + 1 is squarefree (no counterexamples are known). (End)
Alternatively, a(n) is the only k such that A023394(n) divides A000215(k). - Lorenzo Sauras Altuzarra, Feb 01 2023
LINKS
Lorenzo Sauras-Altuzarra, Some properties of the factors of Fermat numbers, Art Discrete Appl. Math. (2022).
PROG
(PARI) forprime(p=3, , r=znorder(Mod(2, p)); hammingweight(r)==1&&print1(logint(r, 2)-1, ", ")) \\ Jeppe Stig Nielsen, Mar 04 2018
CROSSREFS
Sequence in context: A193971 A258861 A171038 * A316655 A318848 A193798
KEYWORD
nonn,more
AUTHOR
EXTENSIONS
a(25)-a(41) computed using data from Wilfrid Keller by T. D. Noe, Feb 01 2009
Three more terms by T. D. Noe, Feb 03 2009
Six more terms from Wilfrid Keller by T. D. Noe, Jan 14 2013
STATUS
approved

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Last modified July 6 14:15 EDT 2024. Contains 374057 sequences. (Running on oeis4.)