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A022126 Fibonacci sequence beginning 3, 16. 1
3, 16, 19, 35, 54, 89, 143, 232, 375, 607, 982, 1589, 2571, 4160, 6731, 10891, 17622, 28513, 46135, 74648, 120783, 195431, 316214, 511645, 827859, 1339504, 2167363, 3506867, 5674230, 9181097, 14855327, 24036424, 38891751, 62928175, 101819926, 164748101 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,1

COMMENTS

a(n) is the sum of eleven consecutive Fibonacci numbers. a(n) = F(n-6) + F(n-5) + ... + F(n+4), where F(n) = A000045(n), extended so that F(-1) = 1, F(-2) = -1, F(-3) = 2, etc. using the rule F(n-1) = F(n+1) - F(n). - Graeme McRae, Apr 24 2014

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 0..1000

Tanya Khovanova, Recursive Sequences

Index entries for linear recurrences with constant coefficients, signature (1, 1).

FORMULA

a(0) = 3, a(1) = 16, a(n) = a(n - 2) + a(n - 1).

G.f.: (3 + 13x)/(1 - x - x^2). - Philippe Deléham, Nov 19 2008

From Colin Barker, Jun 03 2016: (Start)

a(n) = (2^(-1 - n)*((1 - sqrt(5))^n*(-29 + 3*sqrt(5)) + (1 + sqrt(5))^n*(29 + 3*sqrt(5))))/sqrt(5).

a(n) = a(n-1) + a(n-2) for n > 1.

(End)

E.g.f.: (29*sqrt(5)*sinh(sqrt(5)*x/2) + 15*cosh(sqrt(5)*x/2))*exp(x/2)/5. - Ilya Gutkovskiy, Jun 03 2016

MAPLE

seq(coeff(series((3+13*x)/(1-x-x^2), x, n+1), x, n), n = 0 .. 40); # Muniru A Asiru, Sep 29 2018

MATHEMATICA

CoefficientList[Series[(3 + 13 x)/(1 - x - x^2), {x, 0, 40}], x] (* Vincenzo Librandi, Apr 25 2014 *)

LinearRecurrence[{1, 1}, {3, 16}, 50] (* Alonso del Arte, Sep 29 2018 *)

PROG

(PARI) Vec((3+13*x)/(1-x-x^2) + O(x^100)) \\ Colin Barker, Jun 03 2016

(GAP) a:=[3, 16];; for n in [3..40] do a[n]:=a[n-1]+a[n-2]; od; a; # Muniru A Asiru, Sep 29 2018

CROSSREFS

Sequence in context: A219508 A032922 A103655 * A127006 A042075 A042777

Adjacent sequences:  A022123 A022124 A022125 * A022127 A022128 A022129

KEYWORD

nonn,easy

AUTHOR

N. J. A. Sloane

STATUS

approved

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Last modified October 16 23:12 EDT 2018. Contains 316275 sequences. (Running on oeis4.)