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A016552
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Continued fraction for log(49/2).
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2
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3, 5, 29, 1, 17, 2, 7, 5, 1, 8, 9, 20, 1, 2, 1, 1, 1, 2, 4, 1, 4, 1, 4, 3, 1, 1, 1, 3, 1, 1, 1, 1, 5, 1, 22, 2, 2, 31, 2, 41, 1, 1, 1, 1, 2, 1, 7, 6, 3, 2, 3, 2, 1, 3, 1, 8, 1, 4, 1, 1, 1, 4, 20, 1, 1, 2, 1, 4, 1, 3, 4, 5, 1, 2, 1, 157, 1, 22
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OFFSET
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1,1
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LINKS
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EXAMPLE
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3.1986731175506813007934733... = 3 + 1/(5 + 1/(29 + 1/(1 + 1/(17 + ...)))). - Harry J. Smith, May 28 2009
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MATHEMATICA
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ContinuedFraction[Log[49/2], 100] (* Paolo Xausa, Apr 02 2024 *)
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PROG
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(PARI) { allocatemem(932245000); default(realprecision, 21000); x=contfrac(log(49/2)); for (n=1, 20000, write("b016552.txt", n, " ", x[n])); } \\ Harry J. Smith, May 28 2009
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CROSSREFS
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KEYWORD
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nonn,cofr
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AUTHOR
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STATUS
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approved
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