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A003570
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For n>0, a(n) = least positive number m such that 8^m == +1 or -1 (mod 2n + 1), with a(0) = 0 by convention.
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0
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0, 1, 2, 1, 1, 5, 2, 4, 4, 3, 2, 11, 10, 3, 14, 5, 5, 4, 6, 4, 10, 7, 4, 23, 7, 8, 26, 20, 3, 29, 10, 2, 2, 11, 22, 35, 3, 20, 10, 13, 9, 41, 8, 28, 11, 4, 10, 12, 8, 5, 50, 17, 4, 53, 6, 12, 14, 44, 4, 8, 55, 20, 50, 7, 7, 65, 6, 12, 34, 23, 46, 20, 14, 14, 74, 5, 8, 20, 26, 52, 11, 27, 20, 83
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OFFSET
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0,3
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COMMENTS
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Multiplicative suborder of 8 (mod 2n+1) = sord(8, 2n+1). - Harry J. Smith, Feb 11 2005
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REFERENCES
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H. Cohen, Course in Computational Algebraic Number Theory, Springer, 1993, p. 25, Algorithm 1.4.3
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LINKS
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EXAMPLE
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a(1) = 1 since 8^1 = 8 == -1 (mod 3).
a(2) = 2 since 8^2 = 64 == -1 (mod 5).
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MATHEMATICA
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Suborder[k_, n_] := If[n > 1 && GCD[k, n] == 1, Min[MultiplicativeOrder[k, n, {-1, 1}]], 0];
a[n_] := Suborder[8, 2 n + 1];
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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Edited by N. J. A. Sloane, May 22 2008 at the suggestion of Jeremy Gardiner
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STATUS
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approved
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