Talk:A086089

${\frac {3{\sqrt {3}}}{2\pi }}={\frac {1}{\int _{0}^{1}{\frac {1}{(1-x^{3})^{1/3}}}dx}}$ ( verify ) Jaume Oliver Lafont 09:51, 7 July 2010 (UTC)

${\frac {3{\sqrt {3}}}{2\pi }}={\frac {1}{\int _{0}^{1}{\frac {1}{1-x+x^{2}}}dx}}$ ( verify ) Jaume Oliver Lafont 22:04, 8 July 2010 (UTC)