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A365689
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Final decimal digit of n^((n+1)^(n+2)) = A030198(n).
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2
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0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 1, 4, 5, 6
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OFFSET
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0,3
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COMMENTS
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Period 10, repeat: [0, 1, 2, 1, 4, 5, 6, 1, 8, 1].
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,0,1).
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FORMULA
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a(n) = n^((n+1)^(n+2)) mod 10.
a(n) = A103562(n) for n >= 4 (as 3^(2^1) == 9 (mod 10) instead of 1).
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EXAMPLE
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For n = 2, a(2) = 2417851639229258349412352 mod 10 = 2.
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MATHEMATICA
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PadRight[{}, 100, {0, 1, 2, 1, 4, 5, 6, 1, 8, 1}] (* Paolo Xausa, Oct 16 2023 *)
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PROG
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(PARI) a(n) = lift(Mod(n, 10)^((n+1)^(n+2))); \\ Michel Marcus, Sep 16 2023
(Python)
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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