A246921 Irregular triangular array: row n gives numbers D, each being the discriminant of the minimal polynomial of a quadratic irrational represented by a continued fraction with period an n-tuple of 1s and 3s.

5, 13, 5, 13, 21, 5, 13, 17, 65, 5, 13, 21, 165, 725, 2805, 5, 13, 445, 1525, 1853, 5933, 7925, 30629, 5, 13, 17, 21, 65, 136, 288, 960, 1260, 4224, 16128, 21608, 83520, 5, 13, 3029, 10205, 11029, 12773, 28157, 34973, 42853, 47965, 53365, 136165, 184045

Offset

1,1

Links

Table of n, a(n) for n=1..49.

Example

First 5 rows:
5 ... 13
5 ... 13 ... 21
5 ... 13 ... 17 .. 65
5 ... 13 ... 21 .. 165 .. 725 .. 2805
5 ... 13 ... 445 . 1525 . 1853 . 5933 . 7925 . 30629
The following list shows for n = 3 the purely periodic continued fractions (with period an n-tuple of 1s and 2s), each followed by the number r it represents, the minimal polynomial a*x^2 + b*x + c of r, and the discriminant, D = b^2 - 4*a*c.
[(1,1,1)] = (1+sqrt(5))/2, -1 - x + x^2, D = 5
[(1,1,3)] = (-1 + sqrt(17)/2, -4 + x + x^2, D = 17
[(1,3,1)] = (3 + sqrt(17)/4, -1 - 3 x + 2 x^2, D = 17
[(3,1,1)] = (-1 + Sqrt[65])/4, -8 + x + 2 x^2, D = 65
[(1,3,3)] = (1 + sqrt(17)/4, -2 - x + 2 x^2, D = 17
[(3,1,3)] = (-3 + sqrt(65))/4, -7 + 3 x + 2 x^2, D = 65
[(3,3,3)] = (5 + sqrt(65))/10, -2 - 5 x + 5 x^2, D = 65
[(3,3,3)] = (-1 + sqrt(13))/2, -3 + x + x^2, D = 13
The distinct values of D are 5, 13, 17, 65, as in row 3.

Mathematica

z = 7; u[n_] := u[n] = Table[MinimalPolynomial[Map[FromContinuedFraction[{1, #}] &, Tuples[{1, 3}, k]], x], {k, 1, n}]; d = Discriminant[u[z], x];
t = Table[Union[d[[n]]], {n, 1, z}]; TableForm[t] (* A246921 array *)
Flatten[t] (* A246921 sequence *)

Crossrefs

Cf. A246904, A246922.

Sequence in context: A297903 A298497 A246922 * A170864 A293958 A089619

Adjacent sequences: A246918 A246919 A246920 * A246922 A246923 A246924

Keyword

nonn,tabf,easy

Author

Clark Kimberling, Sep 07 2014

Status

approved