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A213908
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Minimal number of terms in the series 1/n + 1/(n+1) + 1/(n+2) + ... to obtain a sum >= 1.
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1
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1, 3, 5, 7, 8, 10, 12, 13, 15, 17, 19, 20, 22, 24, 25, 27, 29, 31, 32, 34, 36, 37, 39, 41, 43, 44, 46, 48, 49, 51, 53, 55, 56, 58, 60, 62, 63, 65, 67, 68, 70, 72, 74, 75, 77, 79, 80, 82, 84, 86, 87, 89, 91, 92, 94, 96, 98, 99, 101, 103, 104, 106, 108, 110
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OFFSET
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1,2
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LINKS
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FORMULA
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EXAMPLE
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a(3)=5 because 1/3 + 1/4 + 1/5 + 1/6 < 1 (4 terms), but 1/3 + 1/4 + 1/5 + 1/6 + 1/7 >= 1 (5 terms).
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MATHEMATICA
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i = 0; s = 0; Table[While[s < 1, i++; s = s + 1/i]; s = s - 1/n; i - n + 1, {n, 100}] (* T. D. Noe, Jun 26 2012 *)
With[{nn=100}, Table[Position[Accumulate[1/Range[n, 2 nn]], _?(#>=1&), 1, 1], {n, nn}]]//Flatten (* Harvey P. Dale, May 09 2021 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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