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 A210889 Number of days after Mar 01 00 such that the date written in the format D.M.YY (and considered as a number without the dots) is palindromic. 5
 315, 346, 374, 405, 435, 466, 496, 527, 558, 619, 690, 721, 749, 780, 810, 841, 871, 902, 933, 994, 1065, 1124, 1155, 1185, 1216, 1246, 1277, 1308, 1369, 3958, 3968, 3999, 4027, 4058, 4088, 4119, 4149, 4180, 4211, 4231, 4262, 4272, 4292, 4324, 4343, 4374, 4403, 4434, 4464, 4495, 4525, 4556, 4587, 4598, 4629, 4648, 4659, 4691, 4719, 4778, 4839, 4900 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS There are exactly 322 such palindromic dates between Mar 1 00 and Dec 31 99 (see b-file for the complete list). See A210890 for the corresponding dates. The definition is different from A210891 in that the dates are considered as numbers. The reference date Mar 1 00 makes sense, since this definition results in a sequence which is independent from the leap year / non-leap year property of the reference year '00'. LINKS Hieronymus Fischer, Table of n, a(n) for n = 1..322 EXAMPLE The first palindromic date in D.M.YY format after 'Jan 01 00' is A210890(1)=10101 (= '10.1.01' = 'Jan 10 01' = 'Mar 01 00' + 315 days); The 10th palindromic date in D.M.YY format after 'Jan 01 00' is A210890(10)=101101 (= '10.11.01' = 'Nov 10 01' = 'Mar 01 00' + 619 days); The 44th palindromic date in D.M.YY format after 'Jan 01 00' is A210890(44)=2112 (= '2.1.12' = 'Jan 2 12' = 'Mar 01 00' + 4324 days); The last (322nd) palindromic date in D.M.YY format after 'Jan 01 00' is A210890(322)=9999 (= '9.9.99' = 'Sep 09 99' = 'Mar 01 00' + 36351 days). CROSSREFS Cf. A210883-A210888, A210890-A210895, A106605, A107273, A107275. Sequence in context: A104819 A283901 A207148 * A210891 A076648 A323380 Adjacent sequences:  A210886 A210887 A210888 * A210890 A210891 A210892 KEYWORD nonn,base AUTHOR Hieronymus Fischer, Apr 01 2012 STATUS approved

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Last modified December 15 00:30 EST 2019. Contains 329988 sequences. (Running on oeis4.)