|
|
A160959
|
|
a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 10.
|
|
1
|
|
|
1023, 522753, 10067343, 133824768, 499511463, 5144412273, 6880289823, 34259140608, 66051837423, 255250357593, 241218048687, 1316969541888, 904033571463, 3515828099553, 4915692307383, 8770339995648, 7582212353463, 33752488923153, 18339417490383, 65344091543808
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
LINKS
|
|
|
FORMULA
|
Sum_{k=1..n} a(k) ~ c * n^9, where c = (341/3) * Product_{p prime} (1 + (p^8-1)/((p-1)*p^9)) = 220.6296374... .
Sum_{k>=1} 1/a(k) = (zeta(8)*zeta(9)/1023) * Product_{p prime} (1 - 2/p^9 + 1/p^17) = 0.0009795392562... . (End)
|
|
MATHEMATICA
|
f[p_, e_] := p^(8*e - 8) * (p^9-1) / (p-1); a[1] = 1023; a[n_] := 1023 * Times @@ f @@@ FactorInteger[n]; Array[a, 25] (* Amiram Eldar, Nov 08 2022 *)
|
|
PROG
|
(PARI) a(n) = {my(f = factor(n)); 1023 * prod(i = 1, #f~, (f[i, 1]^9 - 1)*f[i, 1]^(8*f[i, 2] - 8)/(f[i, 1] - 1)); } \\ Amiram Eldar, Nov 08 2022
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|