

A141065


List of different composite numbers in Pascallike triangles with index of asymmetry y = 1 and index of obliqueness z = 0 or z = 1.


14



4, 12, 20, 28, 33, 46, 54, 63, 69, 88, 168, 70, 143, 161, 289, 232, 567, 594, 169, 376, 399, 817, 1194, 407, 609, 934, 1778, 1820, 2355, 408, 975, 986, 2150, 3789, 4570, 984, 1596, 2316, 4862, 5646, 7922, 8745, 985, 2367, 2583, 9849, 10801, 16281, 16532, 4180, 5667, 17091, 23585, 30923, 32948, 2378
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OFFSET

1,1


COMMENTS

For the Pascallike triangle G(n, k) with index of asymmetry y = 1 and index of obliqueness z = 0, which is read by rows, we have G(n, 0) = G(n+1, n+1) = 1, G(n+2, n+1) = 2, G(n+3, k) = G(n+1, k1) + G(n+1, k) + G(n+2, k) for n >= 0 and k = 1..(n+1).
For the Pascallike triangle G(n, k) with index of asymmetry y = 1 and index of obliqueness z = 1, which is read by rows, we have G(n, n) = G(n+1, 0) = 1, G(n+2, 1) = 2, G(n+3, k) = G(n+1, k1) + G(n+1, k2) + G(n+2, k1) for n >= 0 and k = 2..(n+2).
From Petros Hadjicostas, Jun 09 2019: (Start)
For the triangle with index of asymmetry y = 1 and index of obliqueness z = 0, read by rows, we have G(n, k) = A140998(n, k) for 0 <= k <= n.
For the triangle with index of asymmetry y = 1 and index of obliqueness z = 1, read by rows, we have G(n, k) = A140993(n+1, k+1) for 0 <= k <= n.
Thus, except for the unfortunate shifting of the indices by 1, triangular arrays A140998 and A140993 are mirror images of each other.
As suggested by R. J. Mathar for sequence A141064, in each row of A140998, the composites not appearing in earlier rows are collected, sorted, and added to the sequence.
Obviously, instead of working with A140998, we may work with A140993: in each row of A140993, the primes not appearing in earlier rows may be collected, sorted, and added to the sequence.
Finally, we explain the meaning of the double recurrence in the attached photograph (about Stepan's triangles and Pascal's triangles).
The creator of the stone slab uses the notation G_n^k to denote either one of the two double arrays G(n, k) described above.
On the stone slab, the letter s is used to denote the "index of asymmetry" (denoted by y here) and the letter e is used to denote the 01 "index of obliqueness" (denoted by z here). Thus, as described above, there are two kinds of StepanPascal triangles depending one whether e = z equals 0 or 1.
If e = 0, the value of k goes from 1 to n + 1, whereas if e = 1 the value of k goes from s + 1 = y + 1 (= 2 here) to n + s + 1 = n + y + 1.
The "index of asymmetry" s = y can take any (fixed) integer value from 0 to infinity. The fixed value of s = y determines the number of initial conditions: G(n + x + 1, n  e*n + e*x  e + 1) = 2^x for x = 0, 1, ..., s = y. In addition, there is one more initial condition: G(n, e*n) = 1.
The "index of asymmetry" s = y also determines the order of the recurrence (which is probably s + 2 = y + 2): G(n + s + 2, k) = G(n + 1, k  e*s + e  1) + Sum_{1<= m <= s + 1} G(n + m, k  e*s + m*e  2*e).
Apparently, for convenience, the author of the current sequence has shifted the indices of the recurrences that appear on the stone slab (see at the beginning of the comments).
(End)


LINKS

Petros Hadjicostas, Table of n, a(n) for n = 1..120
JuriStepan Gerasimov, Stepan's triangles and Pascal's triangle are connected by the recurrence relation ...


EXAMPLE

Pascallike triangle with y = 1 and z = 0 (i.e., A140998) begins as follows:
1, so no composites.
1 1, so no composites.
1 2 1, so no composites.
1 4 2 1, so a(1) = 4.
1 7 5 2 1, so no composites.
1 12 11 5 2 1, so a(2) = 12.
1 20 23 12 5 2 1, so a(3) = 20.
1 33 46 28 12 5 2 1, so a(4) = 28, a(5) = 33, and a(6) = 46.
1 54 89 63 29 12 5 2 1, so a(7) = 54 and a(8) = 63.
1 88 168 137 69 29 12 5 2 1, so a(9) = 69, a(10) = 88, and a(11) = 168.
1 143 311 289 161 70 29 12 5 2 1, so a(12) = 70, a(13) = 143, a(14) = 161, and a(15) = 289.
1 232 567 594 367 168 70 29 12 5 2 1, so a(16) = 232, a(17) = 567, and a(18) = 594.
... [example edited by Petros Hadjicostas, Jun 11 2019]


MAPLE

# This is a modification of R. J. Mathar's program for A141031 (for the case y = 4 and z = 0).
# Construction of array A140998 (y = 1 and z = 0):
A140998 := proc(n, k) option remember; if k < 0 or n < k then 0; elif k = 0 or k = n then 1; elif k = n  1 then 2; else procname(n  1, k) + procname(n  2, k) + procname(n  2, k  1); end if; end proc;
# Construction of the current sequence:
A141065 := proc(nmax) local a, b, n, k, new; a := []; for n from 0 to nmax do b := []; for k from 0 to n do new := A140998(n, k); if not (new = 1 or isprime(new) or new in a or new in b) then b := [op(b), new]; end if; end do; a := [op(a), op(sort(b))]; end do; RETURN(a); end proc;
# Generation of terms of the current sequence:
A141065(24);
# If one wishes to sort composites, the he or she may replace RETURN(a) in the above Maple code with RETURN(sort(a)). In such a case, however, the output sequence is not uniquely defined because it depends on the maximum n.  Petros Hadjicostas, Jun 15 2019


CROSSREFS

Cf. A140993 (mirror image of A140998 with y = 1 and z = 1), A140994 (triangle when y = 2 and z = 1), A140995 (triangle when y = 3 and z = 1), A140996 (triangle when y = 3 and z = 0), A140997 (triangle when y = 2 and z = 0), A140998 (has the above triangle with y = 1 and z = 0), A141020, A141021, A141064 (has primes for y = 1), A141066 (has composites when y = 2), A141067 (has primes when y = 2), A141068 (has primes when y = 3), A141069 (has composites when y = 3).
Sequence in context: A269931 A043437 A213258 * A190748 A273253 A031065
Adjacent sequences: A141062 A141063 A141064 * A141066 A141067 A141068


KEYWORD

nonn


AUTHOR

JuriStepan Gerasimov, Jul 14 2008


EXTENSIONS

Partially edited by N. J. A. Sloane, Jul 18 2008


STATUS

approved



