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 A127803 Inverse of number triangle A(n,k) = 1/(2*2^n-1) if k <= n <= 2k, 0 otherwise. 1
 1, 0, 3, 0, -3, 7, 0, 3, -7, 15, 0, 0, 0, -15, 31, 0, -3, 7, 0, -31, 63, 0, 0, 0, 0, 0, -63, 127, 0, 3, -7, 15, 0, 0, -127, 255, 0, 0, 0, 0, 0, 0, 0, -255, 511, 0, 0, 0, -15, 31, 0, 0, 0, -511, 1023, 0, 0, 0, 0, 0, 0, 0, 0, 0, -1023, 2047 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 COMMENTS Row sums are A127804. LINKS EXAMPLE Triangle begins   1;   0,  3;   0, -3,  7;   0,  3, -7,  15;   0,  0,  0, -15,  31;   0, -3,  7,   0, -31,  63;   0,  0,  0,   0,   0, -63,  127;   0,  3, -7,  15,   0,   0, -127,  255;   0,  0,  0,   0,   0,   0,    0, -255,  511;   0,  0,  0, -15,  31,   0,    0,    0, -511,  1023;   0,  0,  0,   0,   0,   0,    0,    0,    0, -1023, 2047;   ... Inverse of   1;   0, 1/3;   0, 1/7, 1/7;   0,  0,  1/15, 1/15;   0,  0,  1/31, 1/31,  1/31;   0,  0,   0,   1/63,  1/63,  1/63;   0,  0,   0,   1/127, 1/127, 1/127,  1/127;   0,  0,   0,    0,    1/255, 1/255,  1/255,  1/255;   0,  0,   0,    0,    1/511, 1/511,  1/511,  1/511,  1/511;   0,  0,   0,    0,     0,    1/1023, 1/1023, 1/1023, 1/1023, 1/1023;   0,  0,   0,    0,     0,    1/2047, 1/2047, 1/2047, 1/2047, 1/2047, 1/2047;   ... MATHEMATICA rows = 11; A[n_, k_] := If[k <= n, If[n <= 2 k, 1/(2*2^n - 1), 0], 0]; T = Table[A[n, k], {n, 0, rows-1}, {k, 0, rows-1}] // Inverse; Table[T[[n, k]], {n, 1, rows}, {k, 1, n}] // Flatten (* Jean-François Alcover, Jul 03 2018 *) PROG (PARI) B(n, k) = if(k<=n, if(n<=2*k, 1/(2*2^n-1), 0), 0); lista(nn) = {my(m = matrix(nn, nn, n, k, B(n-1, k-1))^(-1)); for (n=1, nn, for (k=1, n, print1(m[n, k], ", "); ); print(); ); } \\ Michel Marcus, Jul 03 2018 CROSSREFS Cf. A127804. Sequence in context: A165012 A198126 A074694 * A021771 A154853 A139214 Adjacent sequences:  A127800 A127801 A127802 * A127804 A127805 A127806 KEYWORD sign,tabl AUTHOR Paul Barry, Jan 29 2007 STATUS approved

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Last modified January 23 01:48 EST 2020. Contains 331166 sequences. (Running on oeis4.)