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A114150
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Triangle, read by rows, given by the product R^2*Q^-1 = Q^3*P^-2 using triangular matrices P=A113370, Q=A113381, R=A113389.
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9
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1, 4, 1, 28, 7, 1, 326, 91, 10, 1, 5702, 1722, 190, 13, 1, 136724, 43764, 4945, 325, 16, 1, 4226334, 1415799, 163705, 10751, 496, 19, 1, 161385532, 56096733, 6617605, 437723, 19896, 703, 22, 1
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OFFSET
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0,2
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COMMENTS
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Complementary to A114151, which gives R^-2*Q^3 = Q^-1*P^2.
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LINKS
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EXAMPLE
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Triangle R^2*Q^-1 = Q^3*P^-2 begins:
1;
4,1;
28,7,1;
326,91,10,1;
5702,1722,190,13,1;
136724,43764,4945,325,16,1;
4226334,1415799,163705,10751,496,19,1; ...
1;
1,1;
1,4,1;
1,28,7,1;
1,326,91,10,1;
1,5702,1722,190,13,1; ...
Thus R^2*Q^-1 = Q^3*P^-2 equals P shift left one column.
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PROG
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(PARI) T(n, k)=local(P, Q, R, W); P=Mat(1); for(m=2, n+1, W=matrix(m, m); for(i=1, m, for(j=1, i, if(i<3 || j==i || j>m-1, W[i, j]=1, if(j==1, W[i, 1]=1, W[i, j]=(P^(3*j-2))[i-j+1, 1])); )); P=W); Q=matrix(#P, #P, r, c, if(r>=c, (P^(3*c-1))[r-c+1, 1])); R=matrix(#P, #P, r, c, if(r>=c, (P^(3*c))[r-c+1, 1])); (R^2*Q^-1)[n+1, k+1]
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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