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A113287 Triangle T, read by rows, where row n of T equals row n of matrix (n+1)-th power of triangle A112555. 5
1, 2, 1, -3, 0, 1, 4, 4, 4, 1, -5, -10, -10, 0, 1, 6, 18, 24, 12, 6, 1, -7, -28, -49, -42, -21, 0, 1, 8, 40, 88, 104, 72, 24, 8, 1, -9, -54, -144, -216, -198, -108, -36, 0, 1, 10, 70, 220, 400, 460, 340, 160, 40, 10, 1, -11, -88, -319, -682, -946, -880, -550, -220, -55, 0, 1 (list; table; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

Remarkably, the matrix logarithm (A113290) is an integer triangle. Matrix m-th power of A112555 = I + m*(A112555 - I) where I = identity matrix.

LINKS

Table of n, a(n) for n=0..65.

FORMULA

G.f.: A(x, y) = 1/(1-x*y) + x*(x+2)/((1-x*y)^2*(1+x+x*y)^2).

EXAMPLE

Triangle begins:

1;

2,1;

-3,0,1;

4,4,4,1;

-5,-10,-10,0,1;

6,18,24,12,6,1;

-7,-28,-49,-42,-21,0,1;

8,40,88,104,72,24,8,1;

-9,-54,-144,-216,-198,-108,-36,0,1;

10,70,220,400,460,340,160,40,10,1; ...

PROG

(PARI) {T(n, k)=local(x=X+X*O(X^n), y=Y+Y*O(Y^k)); polcoeff(polcoeff(1/(1-x*y)+x*(x+2)/((1-x*y)^2*(1+x+x*y)^2), n, X), k, Y)}

CROSSREFS

Cf. A112555, A113288 (inverse), A113290 (log), A113291, A072374.

Sequence in context: A126988 A280499 A130026 * A195665 A096798 A158902

Adjacent sequences:  A113284 A113285 A113286 * A113288 A113289 A113290

KEYWORD

sign,tabl

AUTHOR

Paul D. Hanna, Oct 23 2005

STATUS

approved

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Last modified November 14 04:56 EST 2019. Contains 329110 sequences. (Running on oeis4.)