OFFSET
1,1
COMMENTS
The ratio k(n) /(2*j(n)) tends to sqrt(6) as n increases.
k(n) = 2*b + 1, for n > 0, where b is a side of the Heronian triangle (5, b, b+1). - Andrés Ventas, Dec 13 2024
LINKS
Index entries for linear recurrences with constant coefficients, signature (0,0,10,0,0,-1).
FORMULA
Recurrence: k(1)=5, k(2)=7, k(3)=11, k(4)=25, k(5)=10*k(2)-k(3), k(6)=10*k(3)-k(2) then k(n)=10*k(n-3)-k(n-6).
From Ralf Stephan, Nov 15 2010: (Start)
G.f.: (-7x^5-11x^4-25x^3+11x^2+7x+5)/(x^6-10x^3+1).
PROG
(PARI) Vec(-x*(7*x^5+11*x^4+25*x^3-11*x^2-7*x-5)/(x^6-10*x^3+1) + O(x^100)) \\ Colin Barker, Apr 16 2014
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Pierre CAMI, Apr 29 2005
EXTENSIONS
More terms from Ralf Stephan, Nov 15 2010
More terms from Colin Barker, Apr 16 2014
STATUS
approved