| a(n)= A054413(n-1)^2, n>=1. a(0)=0.
a(n)= 50*a(n-1) + 50*a(n-2) - a(n-3), n>=3; a(0)=0, a(1)=1, a(2)=49.
a(n)= 51*a(n-1) - a(n-2) - 2*(-1)^n, n>=2; a(0)=0, a(1)=1.
a(n)= 2*(T(n, 51/2)-(-1)^n)/53 with twice the Chebyshev's polynomials of the first kind: 2*T(n, 51/2)=A099368(n).
G.f.: x*(1-x)/((1-51*x+x^2)*(1+x)) = x*(1-x)/(1-50*x-50*x^2+x^3).
a(n)=-(2/53)*(-1)^n+(1/53)*[51/2-(7/2)*sqrt(53)]^n+(1/53)*[51/2+(7/2)*sqrt(53)]^n, with n>=0 [From Paolo P. Lava (paoloplava(AT)gmail.com), Aug 28 2008]
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