| a(n)= A041041(n-1)^2, n>=1, a(0)=0.
a(n)= 101*a(n-1) + 101*a(n-2) - a(n-3), n>=3; a(0)=0, a(1)=1, a(2)=100.
a(n)= 102*a(n-1) - a(n-2) - 2*(-1)^n, n>=2; a(0)=0, a(1)=1.
a(n)= (T(n, 51)-(-1)^n)/52 with the Chebyshev's polynomials of the first kind: T(n, 51)=(n).
G.f.: x*(1-x)/((1-102*x+x^2)*(1+x)) = x*(1-x)/(1-101*x-101*x^2+x^3).
a(n)=-(1/52)*(-1)^n+(1/104)*[51+10*sqrt(26)]^n+(1/104)*[51-10*sqrt(26)]^n, with n>=0 [From Paolo P. Lava (paoloplava(AT)gmail.com), Aug 28 2008]
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