OFFSET
0,2
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..300
FORMULA
a(n) = ((n+1)*(2n+5)^n + 1)/(n+2).
MATHEMATICA
Table[((n+1)(2n+5)^n+1)/(n+2), {n, 0, 20}] (* Harvey P. Dale, Oct 06 2019 *)
PROG
(Magma) [((n+1)*(2*n+5)^n+1)/(n+2): n in [0..20]]; // Vincenzo Librandi, Nov 12 2011
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Apr 23 2003
STATUS
approved