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A070272
Numbers n such that reverse(n) = phi(n) + sigma(n).
6
275, 295, 2995, 299995, 2999995, 278736495, 299999995, 299999999995
OFFSET
1,1
COMMENTS
For n>0 5*(6*10^A056716(n)-1) is in this sequence. In fact if p = 6*10^n-1 is prime and n>0 (p>5) then m = 5*p is in the sequence. That's because phi(m) = phi(5*p) = 4*(6*10^n-2) = 24*10^n-8 and sigma(m)= 6*6*10^n, so phi(m) + sigma(m) = 6*10^(n+1)-8 = 5.(9)(n).2 = reversal(2.(9)(n).5) = reversal (3*10^(n+1)-5) = reversal(m)(dot between numbers means concatenation and "(9)(n)" means number of 9's is n). For example 299999995 is in the sequence because 6*10^7-1 is prime and 299999995 = 5*(6*10^7-1); 299999999995 is in sequence because 6*10^10-1 is prime and 299999999995 = 5*(6*10^10-1). Next term is greater than 80000000. - Farideh Firoozbakht, Jan 11 2005
Next term is greater than 10^9. - Farideh Firoozbakht, Jan 23 2005
a(9) > 10^13. - Giovanni Resta, Feb 08 2014
EXAMPLE
Reverse(275) = 572 = 200 + 372 = phi(275) + sigma(275).
MATHEMATICA
Select[Range[10^6], FromDigits[Reverse[IntegerDigits[ # ]]] == EulerPhi[ # ] + DivisorSigma[1, # ] &]
CROSSREFS
Sequence in context: A214111 A344731 A023681 * A066127 A062377 A157489
KEYWORD
base,nonn
AUTHOR
Joseph L. Pe, May 12 2002
EXTENSIONS
One more term from Farideh Firoozbakht, Jan 11 2005
More terms from Farideh Firoozbakht, Jan 23 2005
a(8) from Giovanni Resta, Nov 03 2012
STATUS
approved