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A006520
Partial sums of A006519.
(Formerly M2344)
8
1, 3, 4, 8, 9, 11, 12, 20, 21, 23, 24, 28, 29, 31, 32, 48, 49, 51, 52, 56, 57, 59, 60, 68, 69, 71, 72, 76, 77, 79, 80, 112, 113, 115, 116, 120, 121, 123, 124, 132, 133, 135, 136, 140, 141, 143, 144, 160, 161, 163, 164, 168, 169, 171, 172, 180, 181, 183, 184, 188, 189
OFFSET
1,2
COMMENTS
The subsequence of primes in this partial sum begins: 3, 11, 23, 29, 31, 59, 71, 79, 113, 163, 181. The subsequence of powers in this partial sum begins: 1, 4, 8, 9, 32, 49, 121, 144, 169. - Jonathan Vos Post, Feb 18 2010
REFERENCES
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..1001 [Jul 23 2013; offset adapted by Georg Fischer, Jan 27 2020]
Hsien-Kuei Hwang, Svante Janson, and Tsung-Hsi Tsai, Identities and periodic oscillations of divide-and-conquer recurrences splitting at half, arXiv:2210.10968 [cs.DS], 2022, p. 44.
FORMULA
a(n)/(n*log(n)) is bounded. - Benoit Cloitre, Dec 17 2002
G.f.: (1/(x*(1-x))) * (x/(1-x) + Sum_{k>=1} 2^(k-1)*x^2^k/(1-x^2^k)). - Ralf Stephan, Apr 17 2003
a(n) = b(n+1), with b(2n) = 2b(n) + n, b(2n+1) = 2b(n) + n + 1. - Ralf Stephan, Sep 07 2003
a(2^k-1) = k*2^(k-1) = A001787(k) for any k > 0. - Rémy Sigrist, Jan 21 2021
a(n) ~ (1/(2*log(2)))*n*log(n) + (3/4 + (gamma-1)/(2*log(2)))*n, where gamma is Euler's constant (A001620). - Amiram Eldar, Nov 15 2022
MATHEMATICA
Table[ 2^IntegerExponent[n, 2], {n, 1, 70}] // Accumulate (* Jean-François Alcover, May 14 2013 *)
PROG
(PARI) a(n)=sum(i=1, n, 2^valuation(i, 2))
(Python)
def A006520(n): return sum(i&-i for i in range(1, n+1)) # Chai Wah Wu, Jul 14 2022
CROSSREFS
First differences of A022560.
Sequence in context: A047460 A193532 A068056 * A054204 A050003 A002156
KEYWORD
nonn,easy
EXTENSIONS
More terms from Benoit Cloitre, Dec 17 2002
Offset changed to 1 by N. J. A. Sloane, Oct 18 2019
STATUS
approved