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a(n) = n * floor(sqrt(n)).
2

%I #15 Jun 08 2026 00:42:04

%S 0,1,2,3,8,10,12,14,16,27,30,33,36,39,42,45,64,68,72,76,80,84,88,92,

%T 96,125,130,135,140,145,150,155,160,165,170,175,216,222,228,234,240,

%U 246,252,258,264,270,276,282,288,343,350,357,364,371,378,385,392,399,406,413,420

%N a(n) = n * floor(sqrt(n)).

%F a(n^2) = n^3.

%t a[n_]:=n*Floor[Sqrt[n]]; Array[a,61,0] (* _Stefano Spezia_, Jun 04 2026 *)

%o (Python)

%o from math import isqrt

%o def A396752(n): return n * isqrt(n)

%Y Cf. A000196, A028392, A117926.

%K nonn,easy

%O 0,3

%A _Aitzaz Imtiaz_, Jun 04 2026

%E a(0) prepended by and data corrected by _Stefano Spezia_, Jun 04 2026