OFFSET
0,1
COMMENTS
This constant is the area of the roof, while the base of the dome is the interior of the folium of Galileo, one of the four leaves of the quadrifolium, whose area is Pi/8 (A019675).
The volume under the dome is Pi/48.
LINKS
Zarema Seidametova and Valerii Temnenko, Some Geometric Objects Related to a Classical Problem of Galileo, The College Mathematics Journal, Vol. 51, No. 1 (2020), pp. 57-65.
Eric Weisstein's World of Mathematics, Quadrifolium.
FORMULA
Equals Integral_{x=0..Pi/2} f(cos(x)^2) dx, where f(x) = sqrt(1 - 3*x + 4*x^2) * (5 - 9*x + 5*x^2 + 3*x^3) / 6 - (1 + x) * (x^2 - 1/3) / 2 + (1/2) * x^2 * (1 + x) * sqrt(1 - x) * log(((1 - x)^(3/2) + sqrt(1 - 3*x + 4*x^2)) / (sqrt(1 + x) - (1 + x) * sqrt(1 - x))).
EXAMPLE
0.897291807257505298135334708781087967205346224802818...
MATHEMATICA
f[x_] := Sqrt[1 - 3*x + 4*x^2] * (5 - 9*x + 5*x^2 + 3*x^3) / 6 - (1 + x) * (x^2 - 1/3) / 2 + (1/2) * x^2 * (1 + x) * Sqrt[1 - x] * Log[((1 - x)^(3/2) + Sqrt[1 - 3*x + 4*x^2]) / (Sqrt[1 + x] - (1 + x) * Sqrt[1 - x])];
$MaxExtraPrecision = 1000; RealDigits[NIntegrate[f[Cos[x]^2], {x, 0, Pi/2}, WorkingPrecision -> 120]][[1]]
PROG
(PARI) f(x) = sqrt(1 - 3*x + 4*x^2) * (5 - 9*x + 5*x^2 + 3*x^3) / 6 - (1 + x) * (x^2 - 1/3) / 2 + (1/2) * x^2 * (1 + x) * sqrt(1 - x) * log(((1 - x)^(3/2) + sqrt(1 - 3*x + 4*x^2)) / (sqrt(1 + x) - (1 + x) * sqrt(1 - x)));
intnum(x = 0, Pi/2, f(cos(x)^2))
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Amiram Eldar, May 19 2026
STATUS
approved
