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A394657
Number of decompositions of 2n into an unordered sum of two terms of A393798.
0
0, 1, 1, 1, 2, 1, 2, 2, 2, 2, 3, 3, 3, 2, 3, 2, 4, 4, 2, 3, 4, 3, 4, 5, 4, 3, 5, 3, 4, 6, 3, 5, 6, 2, 5, 6, 5, 5, 7, 4, 5, 8, 5, 4, 9, 4, 5, 7, 3, 6, 8, 5, 6, 8, 6, 7, 10, 6, 6, 12, 4, 5, 10, 3, 6, 8, 5, 5, 7, 6, 8, 10, 5, 5, 11, 3, 7, 9, 4, 7, 9, 4, 5, 11, 8
OFFSET
1,5
COMMENTS
The second different term of this sequence to A002375 is a(65).
Conjecture: for n >= 3, this sequence is always positive.
This is a stronger version of the Goldbach Conjecture.
EXAMPLE
For n = 1, 2n = 2, which cannot be presented as the sum of two primes.
For n = 2, 2n = 4 = 2 + 2, thus a(2) = 1.
For 3 <= n <= 64, refer to examples in A002375.
For n = 65, 2n = 130. A393798 up to 130 gives {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113}. We have 130 = 17+113 = 23+107 = 29+101 = 41+89 = 47+83 = 59+71. Six instances found. So a(65)=6.
Where as for A002375, there is one more instance as 3+127, however 127 is not a term in A393798.
MATHEMATICA
a393798 = {2}; Table[s = 2*n; While[a393798[[-1]] < s, p = a393798[[-1]]; q = p; While[q = NextPrime[q]; diff = q - p; f = FactorInteger[diff]; l = Length[f]; f[[l, 1]] > 3]; p = q; AppendTo[a393798, p]]; pos = 0; ct = 0; While[pos++; pos <= Length[a393798], p = a393798[[pos]]; If[p <= n, If[MemberQ[a393798, s - p], ct++]]]; ct, {n, 1, 85}]
KEYWORD
nonn,easy
AUTHOR
Lei Zhou, Mar 27 2026
STATUS
approved