%I #34 May 15 2026 05:39:36
%S 11,-11101,1102,111111101,-11122203,11103,-11112121211101,
%T 1113242533304,-1121433306,111104,11112222323222211101,
%U -1113344758667744405,1122547669966610,-112225544410,1111105,-111122324344444434232211101,11133549812244525939955506,-11226591166972437711015,1123378103995511020,-11223276655515,11111106
%N Triangle read by rows: row n gives y transposed, where y is the solution to the matrix equation M*y=b, where the matrix M and vector b are defined by M(i,j) = ((10^(i+1) + 1)^(j-1) + 9)/10 and b(i) = ((10^(i+1)+1)^n + 9)/10 for 1 <= i,j <= n.
%C This sequence is similar to A292625 and A365450. See the MathOverflow link.
%H Amiram Eldar, <a href="/A394646/b394646.txt">Table of n, a(n) for n = 1..465</a> (first 30 rows, flattened)
%H Ahmad J. Masad, <a href="https://mathoverflow.net/q/281442">Conjecture that relates matrix systems with some polynomials of integer coefficients as solution sets</a>, MathOverflow, Sep 2017.
%e Triangle begins:
%e 11;
%e -11101, 1102;
%e 111111101, -11122203, 11103;
%e -11112121211101, 1113242533304, -1121433306, 111104;
%e 11112222323222211101, -1113344758667744405, 1122547669966610, -112225544410, 1111105;
%e ...
%o (PARI) M(n) = matrix(n, n, i, j, ((10^(i+1) + 1)^(j-1) + 9)/10);
%o b(n) = vector(n, i, ((10^(i+1)+1)^n + 9)/10);
%o row(n) = matsolve(M(n), b(n)~)~;
%Y Cf. A365450, A292625.
%K sign,tabl
%O 1,1
%A _Ahmad J. Masad_, Apr 28 2026