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A394368
Shortest sides z of integer-sided triangles (x <= y <= z) having at least one integral median and such that every integral median m satisfies gcd(x, y, z, m) = 1, ordered by increasing z, then y, then x.
4
5, 5, 7, 6, 7, 9, 10, 7, 7, 8, 12, 11, 11, 9, 16, 11, 8, 12, 9, 10, 9, 17, 13, 12, 9, 16, 16, 9, 13, 18, 11, 15, 19, 13, 13, 15, 14, 14, 11, 16, 10, 17, 12, 10, 22, 15, 19, 20, 11, 17, 21, 17, 13, 17, 17, 20, 11, 11, 16, 23, 26, 17, 29, 13, 15, 15, 14, 11, 19, 11
OFFSET
1,1
COMMENTS
The longest and middle sides are in A394366 and A394367, respectively. The corresponding median values m are in A394369.
EXAMPLE
5 is a term because in the triangle (x, y, z) = (5, 5, 6) the median to z = 6 has length m = 4. It splits z into 3 and 3, yielding two congruent triangles (3, 4, 5), and gcd(5, 5, 6, 4) = 1.
7 is a term because in the triangle (x, y, z) = (7, 8, 9) the median to y = 8 has length m = 7. It splits y into 4 and 4, yielding triangles (4, 7, 7) and (4, 7, 9), and gcd(7, 8, 9, 7) = 1.
8 is a term because in the triangle (x, y, z) = (8, 14, 14) the medians to y = 14 and z = 14 both have length m = 9. Each splits the side into 7 and 7, yielding triangles (7, 8, 9) and (7, 9, 14), and gcd(8, 14, 14, 9) = 1.
MAPLE
# See Huber link in A394366.
KEYWORD
nonn
AUTHOR
Felix Huber, Mar 24 2026
STATUS
approved