%I #10 Jan 07 2026 21:14:47
%S 1,1,1,2,1,2,1,2,4,1,2,1,2,3,6,1,2,4,1,2,3,6,1,2,4,1,2,5,10,1,2,4,1,2,
%T 3,4,6,12,1,2,3,6,1,2,4,8,1,2,4,8,1,2,4,8,16,1,2,3,6,1,2,3,6,9,18,1,2,
%U 4,8,1,2,3,4,6,12,1,2,5,10,1,2,11,22,1,2,4,8,1,2,4,5,10,20
%N Irregular triangle read by rows: the n-th row gives the divisors of phi(n).
%H Stefano Spezia, <a href="/A392217/b392217.txt">Table of n, a(n) for n = 1..13241</a> (first 1000 rows of the triangle)
%H <a href="/index/Di#divisors">Index entries for sequences related to divisors of numbers</a>.
%e The irregular triangle begins as:
%e 1;
%e 1;
%e 1, 2;
%e 1, 2;
%e 1, 2, 4;
%e 1, 2;
%e 1, 2, 3, 6;
%e 1, 2, 4;
%e 1, 2, 3, 6;
%e 1, 2, 4;
%e 1, 2, 5, 10;
%e 1, 2, 4;
%e 1, 2, 3, 4, 6, 12;
%e ...
%t row[n_]:=Divisors[EulerPhi[n]]; Array[row,25]//Flatten
%Y Cf. A000010, A000012 (1st column), A027750, A062402 (row sums), A392218 (row products).
%K nonn,easy,look,tabf
%O 1,4
%A _Stefano Spezia_, Jan 03 2026