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A391387
Irregular triangle read by rows: greatest odd divisor of A391261(n,k), signed; 0 if A391261(n,k) = 0.
1
1, 1, 0, 1, -1, 1, 0, -1, 1, -1, -1, 1, 0, -3, 1, -1, -1, 1, 1, 0, -1, 0, 1, 1, 0, -3, -1, 1, 0, -5, 0, 5, 1, -1, -1, 3, 3, -1, 1, 0, -1, 0, 1, 1, -1, -5, 1, 3, -3, -1, 1, 0, -7, 0, 7, 0, -7, 1, 1, -1, -1, 1, 1, 0, -1, 0, 5, 0, -1, 0, 1, 1, -1, -7, 3, 15, -5, -5, 1, 1
OFFSET
1,14
COMMENTS
The row length is given by A055034(n)+1 = A389480(n,1)+1, n > 1.
Remaining number after factoring out the powers of 2 from A391261(n,k), from which it becomes clear that we defined the greatest odd divisor of 0 to be 0.
FORMULA
T(n,k) = A391261(n,k)/2^A391386(n,k).
EXAMPLE
The 10th row of A391261 is 16, 0, -20, 0, 5; 16 = 2^4*1, 0 = 2^0*0, -20 = 2^2*(-5), 0 = 2^0*0 and 5 = 2^0*5, so row 10 becomes 1, 0, -5, 0, 5.
Triangle begins (0 <= k <= A055034(n)):
n\k 0 1 2 3 4 5 6 7 8 9
1 1
2 1 0
3 1 -1
4 1 0 -1
5 1 -1 -1
6 1 0 -3
7 1 -1 -1 1
8 1 0 -1 0 1
9 1 0 -3 -1
10 1 0 -5 0 5
11 1 -1 -1 3 3 -1
12 1 0 -1 0 1
13 1 -1 -5 1 3 -3 -1
14 1 0 -7 0 7 0 -7
15 1 1 -1 -1 1
16 1 0 -1 0 5 0 -1 0 1
17 1 -1 -7 3 15 -5 -5 1 1
18 1 0 -3 0 9 0 -3
19 1 -1 -1 7 21 -15 -5 5 5 -1
20 1 0 -1 0 19 0 -3 0 1
CROSSREFS
KEYWORD
sign,tabf
AUTHOR
A.H.M. Smeets, Dec 08 2025
STATUS
approved