%I #12 Dec 04 2025 21:26:16
%S 30,60,180,180,1320,990,1710,23760,1320,1560,30600,13566,4290,1710,
%T 567630,391986,2574,51330,9690,46620,4620,18096,249690,32130,9690,
%U 249690,106260,262080,2734374,7980,1139880,328950,666666,17550,215940,1144920,100464,355680,45144,2477574,2702700,82110
%N a(n) is the least number that is the area of a primitive Pythagorean triangle and is the sum of 2*n consecutive primes.
%C Can the area of a primitive Pythagorean triangle can be the sum of an odd number of consecutive primes? The area is always a multiple of 6, so this would require the first of the primes to be 2.
%e a(4) = 180 because the Pythagorean triangle with sides 9, 40, 41 has area 180, and 180 = 11 + 13 + 17 + 19 + 23 + 29 + 31 + 37 is the sum of 8 consecutive primes, and no smaller number works.
%p N:= 10^6: # for terms involving sums of primes <= N
%p isA024365:= proc(a) local eq,xx,yy;
%p eq:= (x^2-y^2)*x*y - a;
%p for xx in numtheory:-divisors(a) do
%p for yy in map(t -> rhs(op(t)), [isolve(subs(x=xx,eq))]) do
%p if igcd(xx,yy) = 1 and xx+yy mod 2 = 1 then return true fi
%p od od;
%p false
%p end proc:
%p P:= select(isprime,[2,seq(i,i=3..10^6,2)]):
%p PS:= ListTools:-PartialSums([0,op(P)]): nPS:= nops(PS):
%p g:= proc(n)
%p local i,v;
%p for i from 1 to nPS-2*n do
%p v:= PS[i+2*n]-PS[i];
%p if isA024365(v) then return v fi
%p od;
%p FAIL
%p end proc:
%p R:= NULL:
%p for n from 1 do
%p v:= g(n);
%p if v = FAIL then break fi;
%p R:= R, v;
%p od:
%p R;
%Y Cf. A024365, A050936, A383395.
%K nonn
%O 1,1
%A _Will Gosnell_ and _Robert Israel_, Nov 30 2025