%I #17 Sep 08 2025 19:54:45
%S 1,0,1,1,36,211,6733,109110,3935179,120852049,5443425654,255558333097,
%T 14770120409245,943648512760656,69287778033581461,5659960611372895981,
%U 516263085381593167788,51978891572002399746295,5755459912529835391400569,696667046057392012794065454
%N Number of partitions of a 2n-set into even blocks of size > 2.
%C a(n) is the number of ways to form even size groups from a total of 2*n people, where each group has at least 4 people.
%F a(n) = (2*n)! * [x^(2*n)] exp(cosh(x) - x^2/2 - 1).
%F a(n) = Sum_{k=2..n} binomial(2*n-1, 2*k-1)*a(n-k) for n > 0, a(0)=1.
%e a(3) = 1 since for 6 people we can form a single group if a group has to have at least 4 people.
%e a(6) = 6733 since for 12 people the number of ways are (number of people in parentheses):
%e 1 group (12): 1 way;
%e 2 groups (8,4): 495 ways;
%e 2 groups (6,6): 462 ways;
%e 3 groups (4,4,4): 5775 ways.
%p b:= proc(n) option remember; `if`(n=0, 1,
%p add(b(n-2*j)*binomial(n-1, 2*j-1), j=2..n/2))
%p end:
%p a:= n-> b(2*n):
%p seq(a(n), n=0..19); # _Alois P. Heinz_, Sep 01 2025
%t a[n_]:=(2*n)!*SeriesCoefficient[Exp[Cosh[x]-x^2/2-1],{x,0,2n}]; Array[a,20,0] (* _Stefano Spezia_, Sep 02 2025 *)
%Y Cf. A000110, A005046.
%K nonn,easy
%O 0,5
%A _Enrique Navarrete_, Sep 01 2025