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A386810
Numbers that have exactly three exponents in their prime factorization that are equal to 5.
7
24300000, 130691232, 170100000, 267300000, 315900000, 413100000, 461700000, 558900000, 653456160, 704700000, 753300000, 899100000, 996300000, 1044900000, 1142100000, 1190700000, 1252332576, 1287900000, 1433700000, 1437603552, 1482300000, 1628100000, 1680700000
OFFSET
1,1
COMMENTS
The asymptotic density of this sequence is Product_{p primes} (1 - 1/p^5 + 1/p^6) * (s(1)^3 + 3*s(1)*s(2) + 2*s(3)) / 6 = 1.38560245036673575581*10^(-8), where s(m) = (-1)^(m-1) * Sum_{p prime} (1/(p^6/(p-1)-1))^m (Elma and Martin, 2024).
LINKS
Ertan Elma and Greg Martin, Distribution of the number of prime factors with a given multiplicity, Canadian Mathematical Bulletin, Vol. 67, No. 4 (2024), pp. 1107-1122; arXiv preprint, arXiv:2406.04574 [math.NT], 2024.
MAPLE
M:= 10^10: # for terms <= M
B:= select(t -> ifactors(t)[2][.., 2]=[1, 1, 1], [$1..floor(M^(1/5))]):
R:= NULL:
for i from 1 to nops(B) do
Q:= select(t -> igcd(t, B[i]) = 1 and not member(5, ifactors(t)[2][.., 2]), [$1 .. M/B[i]^5]);
R:= R, op(B[i]^5 * Q);
od:
sort([R]); # Robert Israel, Aug 03 2025
MATHEMATICA
seq[lim_] := Module[{s = {}, sqfs = Select[Range[Surd[lim, 5]], SquareFreeQ[#] && PrimeNu[#] == 3 &]}, Do[s = Join[s, sqf^5 * Select[Range[lim/sqf^5], CoprimeQ[#, sqf] && !MemberQ[FactorInteger[#][[;; , 2]], 5] &]], {sqf, sqfs}]; Union[s]]; seq[2*10^9]
PROG
(PARI) isok(k) = vecsum(apply(x -> if(x == 5, 1, 0), factor(k)[, 2])) == 3;
CROSSREFS
Numbers that have exactly three exponents in their prime factorization that are equal to k: A386798 (k=2), A386802 (k=3), A386806 (k=4), this sequence (k=5).
Numbers that have exactly m exponents in their prime factorization that are equal to 5: A386807 (m=0), A386808 (m=1), A386809 (m=2), this sequence (m=3).
Sequence in context: A392928 A251248 A135954 * A203260 A268290 A183791
KEYWORD
nonn,easy
AUTHOR
Amiram Eldar, Aug 03 2025
STATUS
approved