OFFSET
1
COMMENTS
LINKS
MathOverflow, What is the smallest cardinality of a self-linked set in a finite cyclic group?, Feb 15 2017.
MathStackExchange, Sparse Cyclic Sum sets, Jul 13 2025.
FORMULA
For prime powers q, a(q^2 + q + 1) = 0.
EXAMPLE
For length 117, either sparse ruler {0, 1, 4, 8, 10, 22, 27, 36, 47, 60, 76, 91} or cyclic sum set {1, 3, 4, 2, 12, 5, 9, 11, 13, 16, 15, 26} has 12 marks or 12 parts. The excess is 12 - (round(sqrt(117 - 1)) + 1) = 0
{{101, 12, {0,1,10,18,22,39,41,44,50,57,77,87}},
{102, 12, {0,1,4,16,19,40,42,50,59,64,70,77}},
{103, 12, {0,1,3,17,29,31,50,56,61,65,83,96}},
{104, 12, {0,1,3,15,17,42,46,55,65,72,83,99}},
{105, 12, {0,1,3,12,20,34,38,53,60,66,76,81}},
{106, 12, {0,1,3,9,19,39,53,61,66,83,90,94}},
{107, 12, {0,1,9,19,24,31,52,56,58,69,72,98}},
{108, 12, {0,1,3,15,21,46,50,59,69,76,87,103}},
{109, 12, {0,1,10,12,14,17,32,40,61,67,85,86}},
{110, 12, {0,1,5,7,15,24,33,36,57,68,70,95}},
{111, 12, {0,1,3,15,35,46,60,64,73,83,90,106}},
{112, 12, {0,1,7,9,21,35,40,53,57,82,98,109}},
{113, 12, {0,1,7,15,20,24,27,53,55,71,92,103}}}.
CROSSREFS
KEYWORD
nonn,hard
AUTHOR
Ed Pegg Jr, Jul 18 2025
STATUS
approved
