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A385847
Decimal expansion of the length of the chord in a circle (in units of the diameter) that splits the area into one and two thirds.
0
9, 6, 4, 2, 6, 7, 0, 7, 4, 2, 8, 3, 8, 9, 7, 2, 8, 4, 0, 6, 9, 6, 4, 0, 8, 5, 2, 8, 9, 2, 7, 5, 2, 4, 9, 4, 8, 7, 6, 3, 5, 8, 9, 0, 0, 4, 4, 5, 7, 7, 7, 9, 9, 2, 1, 3, 7, 1, 8, 1, 7, 0, 5, 1, 8, 2, 8, 4, 4, 5, 4, 2, 7, 3, 5, 9, 7, 7, 4, 2, 8, 9, 8, 3, 1, 8, 6, 3, 4, 9, 6, 3, 4, 6, 0, 3, 2, 9, 1, 2, 2, 6, 6, 5, 5, 1, 4, 1, 5, 4, 6, 2, 0
OFFSET
0,1
COMMENTS
A chord length c and the area A of the circular segment are related by A = Pi^2*[arcsin x - x *sqrt(1-x^2)] where x = c/(2r) is the chord length divided by diameter 2r.
Setting A = Pi^2*r/3 yields this constant here. Setting A=Pi^2*r/2 gives x=1: a chord through the circle center splits the area into two halves.
arccos(x) = 0.268133... rad = 15.36291.. deg is the angle between the chord and the line through the circle center (that cuts it in half) measured at the point where the chord and the line intersect the circle.
FORMULA
Root of arcsin(x) -x * sqrt(1-x^2) = Pi/3.
EXAMPLE
0.96426707428389728406 ... = 1.928534148567794... / 2 .
MATHEMATICA
RealDigits[Chop[x /. FindRoot[ArcSin[x] - x*Sqrt[1 - x^2] - Pi/3, {x, 1}, WorkingPrecision -> 120]]][[1]] (* Amiram Eldar, Apr 17 2026 *)
CROSSREFS
Cf. A192408 (for right hand side Pi/6, splitting area 1:5).
Sequence in context: A331550 A253267 A388562 * A309070 A010544 A343308
KEYWORD
cons,nonn
AUTHOR
R. J. Mathar, Oct 01 2025
STATUS
approved