%I #9 Jun 01 2025 18:52:05
%S 0,1,1,1,2,1,1,5,1,1,9,1,4,16,1,1,33,11,1,65,1,1,142,1,8,257,1,35,513,
%T 1,1,1038,67,1,2049,1,1,4220,39,1,8192,1,259,16385,1,71,32769,515,1,
%U 65550,1,1,132211,1,1,262145,1,2051,524302,263,32,1048577,4096,1,2097153,1,519,4202480,1,1
%N a(n) = 2^n - A129629(n+1).
%C We observe that 2^(n-1) - A129629(n) often equals 1, and otherwise this difference is often the sum of only one or two distinct powers of two.
%o (PARI) A383182(n)=2^n-A129629(n+1)
%Y Cf. A129629.
%K nonn
%O 0,5
%A _M. F. Hasler_, May 27 2025