OFFSET
1,2
COMMENTS
In the first 10,000 terms, there are only 6 instances in which a(n+1) is more than 1 greater than a(n). - Harvey P. Dale, Oct 18 2025
LINKS
Rémy Sigrist, PARI program
EXAMPLE
a(1) = 1.
a(2) must not divide 1; we can take a(2) = 2.
a(3) must not divide 12; we can take a(3) = 5.
MATHEMATICA
nxt[{c_, a_}]:=Module[{k=a+1}, While[Mod[c, k]==0, k++]; {c*10^IntegerLength[k]+k, k}]; NestList[nxt, {1, 1}, 70][[;; , 2]] (* Harvey P. Dale, Oct 18 2025 *)
PROG
(Python)
from itertools import count, islice
def agen(): # generator of terms
an = t = 1
while True:
yield an
an = next(k for k in count(an+1) if t%k != 0)
t = t*10**len(str(an)) + an
print(list(islice(agen(), 54))) # Michael S. Branicky, Mar 26 2025
(PARI) \\ See Links section.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Rémy Sigrist, Mar 25 2025
STATUS
approved
