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A381236
Irregular triangle read by rows: to get row n, take all the numbers that can be obtained by permuting the digits of 9*n, divide them by 9, and arrange them in order.
2
0, 1, 2, 9, 3, 8, 4, 7, 5, 6, 5, 6, 4, 7, 3, 8, 2, 9, 1, 10, 11, 2, 9, 12, 20, 89, 90, 13, 19, 79, 14, 18, 24, 29, 68, 69, 15, 17, 35, 39, 57, 59, 16, 46, 49, 15, 17, 35, 39, 57, 59, 14, 18, 24, 29, 68, 69, 13, 19, 79, 2, 9, 12, 20, 89, 90, 21, 22, 91, 99, 102, 109
OFFSET
0,3
COMMENTS
Suggested by Problem 3(c) of Carter and Russell (1994), pages 12 and 316, to which the answer is row 96 of the present triangle.
REFERENCES
P. J. Carter and K. R. Russell, The IQ Challenge, Barnes and Noble, NY, 1994.
LINKS
EXAMPLE
k 9*k Permutations Divide by 9 Sum
(this sequence) (A381237)
0 0 0 0 0
1 9 9 1 1
2 18 18,81 2,9 11
3 27 27,72 3,8 11
4 36 36,63 4,7 11
5 45 45,54 5,6 11
6 54 45,54 5,6 11
7 63 36,63 4,7 11
8 72 27,72 3,8 11
9 81 18,81 2,9 11
10 90 9,90 1,10 11
11 99 99 11 11
12 108 18,81,108,180,801,810 2,9,12,20,89,90 222
13 117 117,171,711 13,19,79 111
14 126 126,162,216,261,612,621 14,18,24,29,68,69 222
MAPLE
T:= n-> sort(map(x-> parse(cat(x[]))/9,
combinat[permute](convert(9*n, base, 10))))[]:
seq(T(n), n=0..25); # Alois P. Heinz, Mar 17 2025
CROSSREFS
See A381237 for row sums.
Sequence in context: A199604 A260525 A366249 * A394171 A302973 A258403
KEYWORD
nonn,tabf,base
AUTHOR
N. J. A. Sloane, Mar 16 2025
STATUS
approved