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A380104
Minimal conductors c of complex dihedral normal closures K = L(zeta_3) of pure cubic number fields L = Q(d^1/3), d > 1 cubefree, with elementary bicyclic 3-class group Cl_3(K)=(3,3) and second 3-class group M=Gal(F_3^2(K)/K) of assigned coclass cc(M)=0,1,2,3,...
1
30, 90, 418, 1626
OFFSET
1,1
COMMENTS
The coclass cc(M) for one of the fields K with conductor c = a(n) is n-1, and for each field K with conductor c < a(n), the coclass cc(M) is less than n-1. Among the 3-groups M of coclass cc(M)=1, we distinguish the abelian 3-group A=(3,3) by formally putting cc(A)=0, in accordance with the FORMULA. This is a significant difference to quadratic fields, which are firstly uniquely determined by their discriminant, and secondly cannot have an abelian second 3-class group.
LINKS
Siham Aouissi and Daniel C. Mayer, Coclass of the second 3-class group, arXiv:2508.17510 [math.NT], 2025. See p. 12.
Daniel Constantin Mayer, The distribution of second p-class groups on coclass graphs, arXiv:1403.3833 [math.NT], 2014; J. Théor. Nombres Bordeaux 25 (2013), 401-456.
FORMULA
According to Theorem 3.12 on page 435 of "The distribution of second p-class groups on coclass graphs", the coclass of the group M is given by cc(M)+1=log_3(h_3(E_2)), where h_3(E_2) is the second largest 3-class number among the four unramified cyclic cubic extensions E_1,..,E_4 of the complex dihedral field K, and log_3 denotes the logarithm with respect to the basis 3. An exception is the abelian 3-group A=(3,3) with correct cc(A)=1, where the FORMULA yields cc(A)=0.
EXAMPLE
We have M abelian for c=30=2*3*5 (a singlet), cc(M)=1 for c=90=2*3^2*5 (two fields in a quartet), cc(M)=2 for c=418=2*11*19, cc(M)=3 for c=1626=2*3*271.
PROG
(Magma) // See Links section.
CROSSREFS
Analog of A379524 for real quadratic fields.
Sequence in context: A039462 A370495 A138018 * A004995 A042772 A042770
KEYWORD
nonn,hard,more
AUTHOR
STATUS
approved