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%I #11 Dec 11 2024 11:34:44
%S 1,2,3,11,12,435,436,6748,42360,1252676,1252677,302302546,302302547
%N Number of partitions of 1 into {1/1^3, 1/2^3, 1/3^3, ..., 1/n^3}.
%H <a href="/index/Ed#Egypt">Index entries for sequences related to Egyptian fractions</a>
%F a(p) = a(p-1) + 1 for prime p. - _Jinyuan Wang_, Dec 11 2024
%e a(4) = 11 because we have 64 * (1/64) = 56 * (1/64) + 1/8 = 48 * (1/64) + 2 * (1/8) = 40 * (1/64) + 3 * (1/8) = 32 * (1/64) + 4 * (1/8) = 24 * (1/64) + 5 * (1/8) = 16 * (1/64) + 6 * (1/8) = 8 * (1/64) + 7 * (1/8) = 27 * (1/27) = 8 * (1/8) = 1.
%Y Cf. A000578, A020473, A038034, A378270.
%K nonn,more
%O 1,2
%A _Ilya Gutkovskiy_, Nov 21 2024
%E a(9)-a(13) from _Jinyuan Wang_, Dec 11 2024