OFFSET
1,2
EXAMPLE
a(8) = 212 because 212 is the smallest deficient number that begins a run of 8 consecutive deficient numbers (212, 213, 214, 215, 217, 218, 219, 221) with the same number of distinct prime factors, i.e. 2.
a(9) = 295 because 295 is the smallest deficient number that begins a run of 9 consecutive deficient numbers (295, 296, 297, 298, 299, 301, 302, 303, 305) with the same number of distinct prime factors, i.e. 2.
CROSSREFS
KEYWORD
nonn,more,hard
AUTHOR
Shyam Sunder Gupta, Oct 26 2024
STATUS
approved